vertex is (8,-3) also passes through (9,1) whats that in vertex form?
you can use vertex form y=a(x-h)+k (h,k) is the vertex you can plug in a point for (x,y) and solve for a, then you'll have all parts of the equation =D so plugging in 1=a(9-8)-3 can you solve for a?
1=1a-3?
oopsy, i forgot the square, it'll still give us the same result in this case but want you to learn it right. its y=a(x-h)^2+k so we get 1=a(9-8)^2-3 1=1a-3 4=a just tack that into the equation a long with the vertex and you've got your answer y=4(x-8)^2-3
So if im right that's the answer?
yes that is the answer.
thanks do you have time for another question?
sure
Your axis is x=6 and your maximum height is 8 and the line passes through 7,5
I need standard form
is that what the question says
yes
my bad vertex form!
axis of symmetry x=6?
Are ya still here?
yes
ok well if I'm interpreting the question right, its an axis of symmetry. the problem basically gave you a vertex and a point like the last one because the axis of symmetry is the x value of the vertex, and the maximum value is the y value of the vertex. so we have a vertex of (6,8) and a point at (7,5) now its just like the last problem but with different numbers, can you start it off?
help please
5=a(7-6)^2+8 solve for a.
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