Question

Solve for the equation for the interval [0, 2pi)
sin^2x-cos^2x=0

Answer 1

i think i know the answer, hld on let me check

Answer 2

ok

Answer 3

heres the answer

Answer 4

my choices are
A)π4,π3

B)π4,π6

C)π4

D)π4,3π4,5π4,7π4

Answer 5

same here

Answer 6

Try factoring:

sin^2x-cos^2x=0

(sin x + cos x ) * (sin x - cos x ) = 0

Use the Zero Product Property

Answer 7

is it A

Answer 8

(sin x + cos x ) * (sin x - cos x ) = 0

(sin x + cos x )= 0 OR (sin x - cos x ) = 0

sin x = - cos x OR sin x = cos x