\[\[\lim_{x \rightarrow 6}(\frac{ \sqrt[5]{x^2-4}-2 }{ x-6 })\]\]
Evaluate the following limits
@AravindG
HELPP Q~Q
that looks scary
@nincompoop
how is that a logarithmic problem?
in order to solve it im pretty sure u have to log it first
no
so you dont natural log it?
it is up to you, this is where all of your algebra knowledge come into play
your goal is to achieve a non-zero denominator
i do remember you can switch lim and ln around and put lim on outside and ln on inside. i did that and i dont know how to follow up with it. :( im trying to achieve the non zero denominator...
it doesn't matter how crazy your numerator is. your issue will be your denominator being zero
try whatever you're talking about and we'll see how is that going to pan out
\[\lim_{x \rightarrow 6}(\ln (\sqrt[5]{x^2-4}-2) - \ln (x-6))\]
is where i got to.... after using my method
i dont know where to go after that
can you rewrite your question because it is not displaying correctly
This limit problem is a perfect candidate for L'Hopital's Rule.
That explains why I don't get it... our teacher hasn't covered this part yet. Thanks!
how come the problem is not rendering correctly on my screen...?
\[\lim_{x \rightarrow 6}(\frac{ \sqrt[5]{x^2-4}-2 }{ x-6 })\]
^thats the problem if u still want to see it
show the hospital's way (laughing out loud) @Easyaspi314
I am happy to learn this if it didn't give us a DNE
limit DNE
Sure...The derivative of the denominator is just 1...so we just need the derivative of numerator...and that is (using chain rule), (2x/5)(x^2 - 4)^(-4/5)......as x----> 6, that's just 3/20.
|dw:1384498309609:dw|
And it's quite evident from the graph...that it approaches .15 or 3/20.
I graphed it and it gave me asymptotes
Sorry, then you didn't enter it correctly. Be careful as you need parenthesis..plenty of them. I showed a pretty accurate graph of the function.
Enter the function as: ((x^2 - 4)^(.2) - 2)/(x-6)
That should you give the correct graph.
nvm I did a typo I put -2 instead of -4
ok.
it's why I asked you to do l'hospital earlier because the graph I had would not have any limit
it is not rendering properly on my screen
I dont see that on my screen. I see it nicely "typeset".
thanks for your help
no problem. take care.
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