Question

3(2x-1)-2(3x+4)=11x

Answer 1

can you expand this parenthesis.

Answer 2

6x - 3 -6x -8 = 11x

Answer 3

Then you have -11 = 11x

Answer 4

Divide by 11 on both sides.

Answer 5

-1 = x

Answer 6

3(2x-1)-2(3x+4)=11x
6x-3-6x-8=11x
-11=11x
dividing both side by 11
-11/11=11x/11
x=-1

Answer 7

@hihi67, we are here to guide, not give answer!

Answer 8

@Nurali, why are we giving answer?

Answer 9

@Smiler777 Do you understand?

Answer 10

you know this is not right, but still do it, both of you guys!
Please try to help doing a different example, so that the asker can do the problem on his own, with your guidance.

Posting work wiht answers, and certainly just answers, is unacceptable.
@ihi67 @Nurali

Answer 11

@Smiler777, do you want to do a different example to understand how to do this type of problems?

Answer 12

@SolomonZelman tht would help

Answer 13

Ok so lets say you have
\[2(x+3)-x^2-3(x+3)=6\]
What is your first step?

Answer 14

um...expand the parenthesis?

Answer 15

Yes!
Go

Answer 16

Lets start working on \[2(x+3)\]\[2(x+3)=2 \times x + 2 \times 3= 2x+6\]
can you expand \[-3(x+3)\]the same way?

Answer 17

i have no clue

Answer 18

yes

Answer 19

@Smiler777, lets say you have \[a(x+b)\]to expand you would multiply everything inside the parenthesis times a, and then add them.
See how I did\[2(x+3)?\]

Answer 20

ooo. yes i did

Answer 21

Did you expand the parenthesis of
\[2(x+3)\]\[AND\]\[-3(x+3)?\]
Show me what you got for each please.

Answer 22

\[2(x+3)=2 \times x+ 3 \times 2=2x+6\]\[and\]\[-3(x+3)=(-3 \times x)+ (-3 \times 3)=-3x+(-9)=-3x-9\]

Answer 23

2x+6..and i dont know what to do next

Answer 24

Do you see how I expanded, -3(x+3) and 2(x+3)?
Once you got them....
You had
\[2(x+3)-x^2-x(3+x)=6\]
now I substitute, so I get,
\[(2x+6)-x^2(-3x-9) ---> 2x+6-x^2-3x-9=6\]
@Smiler777

Answer 25

See how I substituted?

Answer 26

i see what you did ! but how u got the -9 ?

Answer 27

B/c -3 times 3 is -9

Answer 28

ok so after we substitute.. whats next

Answer 29

So we have \[2x+6-x^2-3x-9=6\]
First subtract 6 from both sides, and then add like terms.

Answer 30

how do we do that . ..like subtract it under both six ?

Answer 31

like,
\[2x+6-x^2-3x-9=6-->2x+6-x^2-3x-9-6=6-6--->\]\[2x+6-x^2-3x-12=0\]
Do you see any like terms?

Answer 32

yes ...6-x2?

Answer 33

I'll rewrite this in a different order,\[-x^2+2x-3x+6-12=0\]

Answer 34

ok ....what do u want me to do ? D: this is hard

Answer 35

Add like terms.

Answer 36

Yes add the like terms together.

Answer 37

\[2x-3x=?\]\[6-12=?\]

Answer 38

@Smiler777

Answer 39

-6x? -6 so there both a like term ?