Question

Solve the exponential inequality.
3^3+x > 729......... for your information 3+x is an exponent

Answer 1

since the exponent is a grouping, in the future you may just want to use ( ) to wrap it up in

3^(3+x) > 729

Answer 2

OK

Answer 3

exponents have the property that: exp(a+b) = exp(a) * exp(b)

Answer 4

3^(3+x) > 729

3^(3) * 3^(x) > 729

3^(x) > 729/27

is a good start

Answer 5

then you'd have 3^(x)>27

Answer 6

correct, which should be small enough to do without a calculator now

Answer 7

so would x equal 9

Answer 8

3^1 = 3
3^2 = 9
3^3 = 27

3^x > 27

3^x > 3^3

x > 3

Answer 9

so the reason we got 3 is because?????

Answer 10

because 27 is equal to 3^3

3^x is greater than 3^3

we are comparing the x values ... if x=3, then 3^3 = 3^3 ... we want it to be greater than

so x has to be greater than 3

Answer 11

we could log it out if you wanted a more mathical approach

3^x > 3^3

log(3^x) > log(3^3)

x log(3) > 3 log(3)

x > 3

Answer 12

THANK YOU i have another question that im half way done with idk if you want to help though

Answer 13

if its small enough sure

Answer 14

ok 5^(2x+2) < 625 and i already have 5^(x+2)<25 whats the next step

Answer 15

split the exponent and divide out the constant

Answer 16

only your setup is flawed

Answer 17

5^(2x+2) < 625

5^[2(x+1)] < 625

25^(x+1) < 625

Answer 18

25^(x+1) < 625

25^(x)+ * 25^(1) < 625

25^(x) < 625/25

Answer 19

second line has a spurious little + hanging in there ... just ignore it lol

Answer 20

25^(x+1) < 625

25^(x)* 25^(1) < 625 ... thats better

25^(x) < 625/25

Answer 21

lol i got 25^x < 25 the answer would be x<1

Answer 22

correct

Answer 23

yea buddy lol thanx my friend that is all

Answer 24

youre welcome ... good luck :)