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Mathematics 8 Online
OpenStudy (anonymous):

if u is a solution to Ax = b and v is a solution for Ax = 0 show u + v is a solution to Ax = b

OpenStudy (anonymous):

let say \[u=\left[\begin{matrix}u_1\\u_2\\..\\..\\..\\u_n\end{matrix}\right]\] is solution of Ax =b , then \(a_{11}u_1+a_{21}u_2+......+a_{mn}un=b_1\) you still have many lines, but I just pick 1 to show. and v is the same \(a_{11}v_1+a_{21}v_2+....+a_{mn}v_n =0\) now add them up, and factor \(a_{ij}\) out \(a_{11}(u_1+v_1)+a_{21}(u_2+v_2)+.....a_{mn}(u_n+v_n) =b_1\) do the same with \(a_{12},a_{13}.....a_{1n}\)you will have (u+v) is the solution of Ax =b I am not sure whether you get my shortcut or not, ok, let me rearrange

OpenStudy (anonymous):

I may get ban from this reply. Whatsoever, I don't care, proving problem is not a problem to teach.

OpenStudy (anonymous):

thanks alot.

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