Determine whether the given quadratic function has a minimum or maximum value. Then find the coordinates of the minimum or maximum point: f(x)=-x^2-2x-6
If the coeffricient of x^2 is positive, then the parabola is U-shaped and has a minimum. If the coefficient of x^2 is a negative number, then it is upside down U, and has a maximum.
The x-coordinate of the max or min will be x = -b/(2a). When you have that number x, subsitute that number into the equation for y, and you will have the coordinates of the max or min.
so you pretty much do the same thing you would do if you were solving to find the vertex?
Yes, the vertex of the parabola is the maximum or minimum point of a parabola.
So the answer is Maximum, (1,-5)?
(-1,-5) my bad
in your equation, you have -x^2, so the coefficient of x^2 is -1, so you know it will be an upside down U, and will have a maximum
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