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Chemistry 9 Online
OpenStudy (anonymous):

Yield Question

OpenStudy (anonymous):

\[C Cl _{4}+2HF ---- CCl _{2}F _{2}+2HCl\] 1.80 moles CCl4 reacts with 3 mols HF as shown with the equation. 1.40 moles CCl2F2 is gathered at the end. What is the percentage yield?

OpenStudy (anonymous):

the answer says 77.8 % but i dont agree can someone show hoe its done?

OpenStudy (anonymous):

@thomaster @radar please?

OpenStudy (zpupster):

1.4moles CCl2F2/1.8 molesCCl4 ==???

OpenStudy (anonymous):

but why?

OpenStudy (zpupster):

you used 1.8 moles and received 1.4 moles if you received 1.8 it would be a 100 per cent.

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