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Yield Question
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\[C Cl _{4}+2HF ---- CCl _{2}F _{2}+2HCl\] 1.80 moles CCl4 reacts with 3 mols HF as shown with the equation. 1.40 moles CCl2F2 is gathered at the end. What is the percentage yield?
the answer says 77.8 % but i dont agree can someone show hoe its done?
@thomaster @radar please?
1.4moles CCl2F2/1.8 molesCCl4 ==???
but why?
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you used 1.8 moles and received 1.4 moles if you received 1.8 it would be a 100 per cent.
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