divide using long division (5x^4-3x^3+x^2-6x+7) ÷ (x^2+1)

Question

jdoe0001 · Answer

$\bf (5x^4-3x^3+x^2-6x+7) \div (x^2+1)\ \quad \\implies (5x^4-3x^3+x^2-6x+7) \div (x^2+0x+1)\ \quad \

\begin{array}{llll}
\hline\
5x^4-3x^3+x^2-6x+7&|
\end{array}\qquad x^2+0x-1$

what do you think would be our 1st number for the quotient?

anonymous · Answer

i'm not sure

jdoe0001 · Answer

ok... what number multiplied by $\bf x^2$   will give us $\bf 5x^4\quad ?$

anonymous · Answer

5^2

jdoe0001 · Answer

25?

anonymous · Answer

i'm not sure i need alot of help haha

anonymous · Answer

can u explain it to me i'm a much better visual learner

jdoe0001 · Answer

$\bf a\cdot x^2=5x^4\implies a=\cfrac{5x^4}{x^2}\implies ?$

a value multiplied by $\bf x^2$ to give us $\bf 5x^4$.... so.. what do you think would be that value "a" ?

jdoe0001 · Answer

http://www.youtube.com/watch?v=l6_ghhd7kwQ <--- this one covers it well

anonymous · Answer

so whats the answer?

jdoe0001 · Answer

dunno