Question

divide using long division (5x^4-3x^3+x^2-6x+7) ÷ (x^2+1)

Answer 1

\(\bf (5x^4-3x^3+x^2-6x+7) \div (x^2+1)\\ \quad \\\implies (5x^4-3x^3+x^2-6x+7) \div (x^2+0x+1)\\ \quad \\

\begin{array}{llll}
\hline\\
5x^4-3x^3+x^2-6x+7&|
\end{array}\qquad x^2+0x-1\)

what do you think would be our 1st number for the quotient?

Answer 2

i'm not sure

Answer 3

ok... what number multiplied by \(\bf x^2\) will give us \(\bf 5x^4\quad ?\)

Answer 4

5^2

Answer 5

25?

Answer 6

i'm not sure i need alot of help haha

Answer 7

can u explain it to me i'm a much better visual learner

Answer 8

\(\bf a\cdot x^2=5x^4\implies a=\cfrac{5x^4}{x^2}\implies ?\)

a value multiplied by \(\bf x^2\) to give us \(\bf 5x^4\).... so.. what do you think would be that value "a" ?

Answer 9

http://www.youtube.com/watch?v=l6_ghhd7kwQ <--- this one covers it well

Answer 10

so whats the answer?

Answer 11

dunno