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the derivative of -5e^(x+3) + e^(-2)
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The e^-2 at the end is a constant, so the derivative of that is 0.
Derivative of e^u is e^u du. So derivative of -5e^(x+3) is -5e^(x+3).
oh so if i wanna find f'(0) just plug 0 into-5e^(x+3)?
Yes, and you get -5e^3.
thx!!
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