Question

Is the line through points P(-8,-10) and Q(-5,-12) perpendicular to the line through points R(9,-6) and S(17,-5)? Explain. Please Help

Answer 1

\(\bf \textit{what is the slope of }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
P&(-8\quad ,&-10)\quad Q&(-5\quad ,&-12)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\\ \quad \\
---------------------\\
\textit{what is the slope of }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
R&(9\quad ,&-6)\quad S&(17\quad ,&-5)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}
\)

Answer 2

-2/3 and 1/8?

Answer 3

hmm... well.... I got ... \(\bf -\cfrac{2}{3}\quad and\quad -\cfrac{14}{23}\) respectively

Answer 4

okay now what?

Answer 5

hmmm hold that... .... hheheeh... I got .... an error

Answer 6

Okay no problem!

Answer 7

anyhow, you're correct

Answer 8

Whoo!

Answer 9

so the slopes are -2/3 and 1/8 so
equations that have graphs that are perpendicular to each other, will have NEGATIVE RECIPROCAL slopes

so the negative reciprocal of -2/3 will be 3/2 and no dice there
the negative reciprocal of 1/8 will be -8 and no dice, thus they're not

Answer 10

thanks!

Answer 11

yw

Answer 12

could you help me with more?