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Mathematics 18 Online
OpenStudy (anonymous):

The path of a football kicked by a field goal kicker can be modeled by the equation y = –0.03x2 + 1.53x, where x is the horizontal distance in yards and y is the corresponding height in yards. Q1: What is the football’s maximum height? Round to the nearest tenth. Q2: How far is the football kicked?

OpenStudy (anonymous):

I would give you the answer if you did not keep deleting your question after I help you out with them. That can also help others.

OpenStudy (anonymous):

i'm not deleting them, i'm just closing them so no one else can answer and confuse people :p

OpenStudy (anonymous):

ok, I'm not gonna give you the answer so that you can actually understand the problem, but I'll tell you this: Q1: You need to find the value at -b/2a Q2: Plug in that value for y Your actual equation is this: y = -.03x^2 + 2.53x Hint: y = ax^2 + bx + c

OpenStudy (anonymous):

this is practice so i'd rather the answer so i can try to solve the equation :p

OpenStudy (anonymous):

Well, just plug in the values: a = -.03 b = 2.53 c = you have no c in this problem

OpenStudy (anonymous):

Q1: -1.26 ?

OpenStudy (anonymous):

2: same?

OpenStudy (anonymous):

i just need the answers. so i can figure the work out lol

OpenStudy (anonymous):

No, I didn't get that for Q1, what I got was 42.1667

OpenStudy (anonymous):

Q1: is 19.5 i just got the answer. how about Q2?

OpenStudy (anonymous):

...

OpenStudy (anonymous):

Plug your answer in for y and solve for x.

OpenStudy (anonymous):

Oh wow I'm so sorry, I rewrote your problem wrong. Here's the actual equation: y = -0.03x^2 + 1.53x Q1: 25.5

OpenStudy (anonymous):

q2?

OpenStudy (anonymous):

I'm getting an imaginary solution for that. I guess that you could put the same as Q1, otherwise it would be weird to have an imaginary distance. Here's what I got: x = 25.5 +- 14.3i

OpenStudy (anonymous):

Was this the original equation, though?\[y = - 0.03x ^{2} + 1.53x\]

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