Question

Holder's Inequality discussion. if you want to talk about it.

Answer 1

What about it?

Answer 2

For all of you that don't know or can't Google: Let \(p, q > 1\) such that \(\frac 1 p + \frac 1 q = 1\). Holder's inequality states when \(|g(x)| = g|f(x)|^{p-1}\) (where g is some constant): $$\int_a^b |f(x) g(x)| \, \mathrm{d}x \leq [\int_a^b |f(x)|^p \, \mathrm{d}x]^{1/p} [\int_a^b |g(x)|^q \, \mathrm{d}x]^{1/q}$$