Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (anonymous):

I need help!!!

OpenStudy (anonymous):

Go on. :3

OpenStudy (anonymous):

√20x^13y^5/5xy^7 a. √4x^12/y^2 b. 2x^6/y c. 2√x^12/y^2 d. 2x^6y

OpenStudy (emilylauren):

is the whole equation under the square root?

OpenStudy (asib1214):

\[√20x^13y^5/5xy^7 \] is this how it looks????

OpenStudy (anonymous):

Yes.

OpenStudy (emilylauren):

If you want me to explain I will :)

OpenStudy (anonymous):

yes please!

OpenStudy (emilylauren):

alright, let's do the top first

OpenStudy (emilylauren):

√20x13y5 the square root of 20 is \[2\sqrt{5}\]

OpenStudy (emilylauren):

so we have \[2\sqrt{5}\] and then the square root of x^13 is \[x^{6}\sqrt{x}\] the square root of y^5 is equal to\[y ^{2}\sqrt{y}\] Does this all make sense so far?

OpenStudy (anonymous):

yes

OpenStudy (emilylauren):

so the top looks like\[2x ^{6}y ^{2}\sqrt{5xy}\]

OpenStudy (emilylauren):

the bottom is 5xy^7 the 5x cannot be simplified but the y^7 becomes \[y ^{3}\sqrt{y}\]

OpenStudy (emilylauren):

so then the bottom is \[y ^{3}\sqrt{5xy}\]

OpenStudy (emilylauren):

combine the top and bottom and you can factor out the \[\sqrt{5xy}\] and a \[y ^{2}\]

OpenStudy (emilylauren):

this leaves you with 2x^6/y which is your answer :)

OpenStudy (emilylauren):

let me know if you have questions

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!