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OpenStudy (anonymous):
Go on. :3
OpenStudy (anonymous):
√20x^13y^5/5xy^7
a. √4x^12/y^2
b. 2x^6/y
c. 2√x^12/y^2
d. 2x^6y
OpenStudy (emilylauren):
is the whole equation under the square root?
OpenStudy (asib1214):
\[√20x^13y^5/5xy^7 \] is this how it looks????
OpenStudy (anonymous):
Yes.
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OpenStudy (emilylauren):
If you want me to explain I will :)
OpenStudy (anonymous):
yes please!
OpenStudy (emilylauren):
alright, let's do the top first
OpenStudy (emilylauren):
√20x13y5
the square root of 20 is \[2\sqrt{5}\]
OpenStudy (emilylauren):
so we have \[2\sqrt{5}\] and then the square root of x^13 is \[x^{6}\sqrt{x}\] the square root of y^5 is equal to\[y ^{2}\sqrt{y}\]
Does this all make sense so far?
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OpenStudy (anonymous):
yes
OpenStudy (emilylauren):
so the top looks like\[2x ^{6}y ^{2}\sqrt{5xy}\]
OpenStudy (emilylauren):
the bottom is 5xy^7
the 5x cannot be simplified but the y^7 becomes \[y ^{3}\sqrt{y}\]
OpenStudy (emilylauren):
so then the bottom is \[y ^{3}\sqrt{5xy}\]
OpenStudy (emilylauren):
combine the top and bottom and you can factor out the \[\sqrt{5xy}\] and a \[y ^{2}\]
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OpenStudy (emilylauren):
this leaves you with 2x^6/y which is your answer :)