Rakesh needs 1.71 g of sugar ($\bf \large C_{12}H_{22}O_{11}$) to sweeten his tea. What would be the number of carbon atoms present in his tea?

$$ \large \bf a) 3.6 \times 10^{22} $$
$$ \large \bf b)7.2 \times 10^{21} $$
$$\large \bf c)0.05 \times 10^{23} $$
$$\large \bf d)6.6 \times 10^{22}$$

Question

Rakesh needs 1.71 g of sugar ($\bf  \large  C_{12}H_{22}O_{11}$) to sweeten his tea. What would be the number of carbon atoms present in his tea?

$$ \large \bf a) 3.6 \times 10^{22} $$
$$ \large \bf b)7.2 \times 10^{21} $$
$$\large \bf  c)0.05 \times 10^{23} $$
$$\large \bf  d)6.6 \times 10^{22}$$

anonymous · Answer

1mole of sugar=342gm
1.71gm=1.71/342moles of sugar=0.005moles

In 1 mole of sugar we have 12*6*10^23 carbon atoms
0.005moles=0.005*12*6*10^23=0.36*10^23

or 3.6*10^22

anonymous · Answer

So what you need to do is convert the grams of super into moles, and then use Avogadro's number to determine the number of atoms in the molecule.
$$1.71g \left( \frac{ 1 mol }{ 342.308g } \right)\left( \frac{ 6.02*10^{23} }{ 1mol } \right)\left( \frac{ 12 atoms }{ 1 molecule } \right)$$