Find the quotient z1/z2 of the complex numbers. Leave answer in polar form.
$$z1 = \frac{ 1 }{ 8 }(\cos \frac{ 2\pi }{ 3 }=i \sin \frac{ 2\pi }{ 3 })$$
$$z2= \frac{ 1 }{ 3 }(\cos \frac{ \pi }{ 4 }+i \sin \frac{ \pi }{ 4 })$$

Question

Find the quotient z1/z2 of the complex numbers. Leave answer in polar form. 
$$z1 = \frac{ 1 }{ 8 }(\cos \frac{ 2\pi }{ 3 }=i \sin \frac{ 2\pi }{ 3 })$$
$$z2= \frac{ 1 }{ 3 }(\cos \frac{ \pi }{ 4 }+i \sin \frac{ \pi }{ 4 })$$

wolf1728 · Answer

Wow - that is beyond my understanding of complex numbers!!

yacoub1993 · Answer

u have no idea what the answer would be

wolf1728 · Answer

Heck no.  I don't even understand the question.

yacoub1993 · Answer

lol...hehee anyways thnxs

wolf1728 · Answer

okay u r welcome

yacoub1993 · Answer

@wolf1728  what about this one
Polar coordinates of a point are given. Find the rectangular coordinates of the point. (-5, -180°)

A. (-5, 0)	

B. (0, -5)	

C. (0, 5)	

D. (5, 0)

wolf1728 · Answer

Rectangular coordinates are properly called Cartesian coordinates. The Cartesian coordinates are (5, 6.123 x 10^-16) I used the calculator here: http://www.engineeringtoolbox.com/converting-cartesian-polar-coordinates-d_1347.html

wolf1728 · Answer

So that makes the answer D

anonymous · Answer

In polar form

$$z=r(\cos \theta + i\sin \theta)=r \ cis\theta=re^{i\theta}$$

$$z_1=r_1e^{i\theta}$$
$$z_2=r_2e^{i\varphi}$$
$$ \frac{z_1}{z_2}=\frac{r_1e^{i\theta}}{r_2e^{i\varphi}}=\frac{r_1}{r_2}e^{i(\theta-\varphi)}$$