Question

What is the equation in point-slope form of the line passing through (0, 2) and (1, 5)?

OPTIONS:
A) y – 5 = 3(x – 1)
B) y – 2 = –3(x – 0)
C) y + 2 = 3(x + 1)
D) y + 5 = –3(x + 1)

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(0\quad ,&2)\quad &(1\quad ,&5)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}
\\ \quad \\

y-y_1=m(x-x_1)\quad \textit{plug in your values and solve for "y"}\)

Answer 2

find the slope first

Answer 3

then use that in the "point-slope form" of \(\bf y-y_1=m(x-x_1)\)

Answer 4

2-5/1-0= -3/1=-3

Answer 5

y-5=-3(x-0)

Answer 6

well. \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(0\quad ,&2)\quad &(1\quad ,&5)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{5-2}{1-0}\)

Answer 7

so that gives you a slope of " 3 "

Answer 8

then pick either point and plug it in the \(\bf y-y_1=m(x-x_1)\)

Answer 9

then solve for "y"

Answer 10

y-5=3(x-0)
y-5=3x+0
y=3x+5
@jdoe0001 ?????

Answer 11

hmmm.... well, you don't have a point of ( 0, 5) for one to use y-5=3(x-0)

Answer 12

(0, 2) and (1, 5) <--- either point will do for the "point-slope" form though

Answer 13

so is A correct?
@jdoe0001

Answer 14

yeap

Answer 15

alright thanks @jdoe0001

Answer 16

yw