Question

Could someone walk me through this:
2^(x+1) = 15

Here's what I've got:
1) (x+1)log2 = log15
2) x+1 = log(15)/log(2)

Am i doing it right?

Answer 1

\[2^{(x+1)}=15\]
Hit both sides with the log.

Answer 2

I got disconnected, sorry.

Answer 3

u r right ! @pabloecortez07

Answer 4

x=(log(15)/log(2))-1

Answer 5

\[(x+1)Log2=Log15\]
Divide both sides by Log2
\[x+1=\frac{Log15}{Log2}\]
\[x=\frac{Log15}{Log2}-1\]

Answer 6

yes, as @CGGURUMANJUNATH, pointed out, you didn't finish, you didn't subtract 1 from both sides.

Answer 7

this would help you more in the future,
http://www.rapidtables.com/math/algebra/Ln.htm#ln rules

Answer 8

Thanks to both of you.

Answer 9

\(\huge {\color{blue} {anytime!} }\)