Could someone walk me through this:
2^(x+1) = 15

Here's what I've got:
1) (x+1)log2 = log15
2) x+1 = log(15)/log(2)

Am i doing it right?

Question

Could someone walk me through this:
2^(x+1) = 15

Here's what I've got:
1) (x+1)log2 = log15
2) x+1 = log(15)/log(2)

Am i doing it right?

solomonzelman · Answer

$$2^{(x+1)}=15$$
Hit both sides with the log.

solomonzelman · Answer

I got disconnected, sorry.

cggurumanjunath · Answer

u r right ! @pabloecortez07

cggurumanjunath · Answer

x=(log(15)/log(2))-1

solomonzelman · Answer

$$(x+1)Log2=Log15$$
Divide both sides by Log2
$$x+1=\frac{Log15}{Log2}$$
$$x=\frac{Log15}{Log2}-1$$

solomonzelman · Answer

yes, as @CGGURUMANJUNATH, pointed out, you didn't finish, you didn't subtract 1 from both sides.

solomonzelman · Answer

anonymous · Answer

Thanks to both of you.

solomonzelman · Answer

$\huge {\color{blue} {anytime!} }$