Question

State the vertical asymptote of the rational function.
f(x) = [(x-3)(x+4)]/(x^2-1)

Answer 1

vertical asymptotes are the zeros of the denominator :)

Answer 2

Ok so following what little I know with Descartes rule of signs That gives me one possible zero. All my answers have 2 zeros exept the on the syays none... What am I doing wrong?
Heres my possible answers:
x = -3, x = 4

x = 3, x = -4

None

x = 1, x = -1

Answer 3

All you have to do to find the vertical asymptotes of a rational function is the denominator to equal zero.
x^2-1 = 0
x^2 = 1
\[x = \pm 1\]