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Mathematics 13 Online
OpenStudy (anonymous):

Solve: Lim x--> infinity sinx/(x^2)

OpenStudy (anonymous):

hint : Squeeze theorem

OpenStudy (anonymous):

need more help ?

OpenStudy (anonymous):

Yes! How would you do it using squeeze theorem?

OpenStudy (anonymous):

because -1<sinx<1 we get -1/x^2 < sinx/x^2 < 1/x^2 what is the limit of both -1/x^2 and 1/x^2 as x goes to inf ?

OpenStudy (anonymous):

0! Thank you!

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