Question

[4_06]Choose the equation below that represents the line passing through the point (-2, -3) with a slope of -6.

Answer 1

were you taught
point-slope form: y - y1 = m(x - x1)
or slope-intercept form: y = mx + b
?

Answer 2

I was taught slope intercept form

Answer 3

okay, so for slope-intercept form: y = mx + b
when m =slope and b = y-intercept
you were given slope = -6
so plug in -6 for m : y = -6x + b
then temporarily plug in a given point to find b
so if the point is (-2, -3) find b when -3 = (-6)(-2) + b

then once you've found b you would plug in what you got for b back into
y = -6x + b to get your equation :)

Answer 4

y = -6x - 15

y = -6x - 20

y = -6x + 15

y = -6x + 20

I have to pick from these and I'm still having difficulty

Answer 5

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&(-2\quad ,&-3)
\end{array}
\\\quad \\

slope = m= -6
\\ \quad \\

y-y_1=m(x-x_1)\quad \textit{plug in your values and solve for "y"}\)

Answer 6

y = mx + b
slope(m) = -6
(-2,-3) x = -2 and y = -3
now we sub
y = mx + b
-3 = -6(-2) + b
-3 = 12 + b (subtract 12 from both sides)
-3 - 12 = b
-15 = b

y = -6x -15