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Geometry 5 Online
OpenStudy (anonymous):

Using complete sentences, write an indirect proof proving that if x = 40, then 5 over 6x − 3 ≠ 22.

OpenStudy (anonymous):

use a proof by contradiction where if \[x \neq 40 \] then \[\frac{ 5 }{ 6x - 3 } = 22\]

OpenStudy (anonymous):

hm.. im actually not 100% sure but this is what i would do... forgot to mention that there is a unique solution such that \[x \in Z\] that satisfies that equation if you negate the statement so you solve for x 5 = 22(6x - 3) 5 = 132x - 66 71 = 132x x = 0.53 but 0.53 is not an integer solution so we have a contradiction here thus if x = 40 then \[\frac{ 5 }{ 6x - 3 } \neq 22\]

OpenStudy (anonymous):

woah I am so confused

OpenStudy (anonymous):

indirect proof also means a proof by contradiction so you must prove that there is something wrong when you do the opposite of the problem

OpenStudy (anonymous):

oh okay so complete sentences would be, Lets say that we switch it around and do x≠40 instead of x≠22. We will do 5 over 6x-3=22 and solve for x. The answer is not an integer solution so we have a contradiction here, thus if x = 40 then.

OpenStudy (anonymous):

actually i found an easier way when you negate the statement it becomes if \[x \neq 40 \] then \[(\exists x \in Z : \frac{ 5 }{ 6x - 3 } = 22) \] The parenthesis is suposed to be curly brace so that means if x = 1 then \[\frac{ 5 }{ 6(1) - 3 } = 22\] but you get 1.667 which does not equal 22 so you have a contradiction and the proof is done

OpenStudy (anonymous):

or then again what i said the first time works better

OpenStudy (anonymous):

because it shows that the unique solution is not an integer solution

OpenStudy (anonymous):

Thank you so much

OpenStudy (anonymous):

your welcome

OpenStudy (anonymous):

so what's the answer then?

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