Question

Can someone explain the remainder theorem to me??

Answer 1

Here:
http://www.purplemath.com/modules/remaindr.htm

Answer 2

@Hero thanks but I still am not too sure on how to fully go through a problem..

Answer 3

Do you have a specific problem you are working on?

Answer 4

I am working on 5 different problems with 5 answer choices @Hero

Answer 5

Okay, post 1 of the problems you are working on

Answer 6

\[x^3-4x^2-4x-5\]

Answer 7

Is that all you were given? If you want help you're going to have to posts the complete problem you are working on.

Answer 8

That polynomial expression alone doesn't represent a problem to be solved.

Answer 9

x^3-4x^2-4x-5
x^3+x^2-3x+9
x^3+4x^2+8x+5
x^3-2x^2+x-2
x^3+x^2+13x+4

answers: x-2
x+1
x-5
x+3
no factor listed for this polynomial

Answer 10

@Hero

Answer 11

And what are the instructions for that again? Are you having a hard time finding the instructions. Often, when given a problem, they usually tell you what you need to do or what you need to find. I cannot infer what needs to be done here.

Answer 12

Use the factor theorem to match the polynomial with its factor.

Answer 13

I asked for help with the remainder theorem but I decided to skip it sorry

Answer 14

For what reason did you skip it?

Answer 15

i accidently put in the wrong problems and just realized it

Answer 16

Anyways, for this problem you have posted, you have to do a few things.

Answer 17

First you have to set each factor equal to zero then solve for x.

Answer 18

x - 2 = 0
x + 1 = 0
x - 5 = 0
x + 3 = 0

Answer 19

When you solve for x, then you'll have the possible x values.

Answer 20

Afterwards you will need to insert each value of x in place of x for each polynomial.

Answer 21

Then evaluate each expression. Whichever one yields zero, is the matching polynomial.

Answer 22

For example,

solving x - 2 = 0

yields x = 2

Answer 23

so -1+1=0

Answer 24

Afterwards you will plug 2 in to each polynomial:

(2)^3-4(2)^2-4(2)-5
(2)^3+(2)^2-3(2)+9
(2)^3+4(2)^2+8(2)+5
(2)^3-2(2)^2+(2)-2
(2)^3+(2)^2+13(2)+4

Answer 25

And whichever one yields zero is the polynomial that includes x - 2 as a factor.

Answer 26

It would be a good idea to use a calculator for this.

Answer 27

none of them equal 0

Answer 28

One of them equals zero because I calculated it myself.

Answer 29

I don't know why i didn't get one then..I will try again

Answer 30

i got all negative numbers

Answer 31

I'm sorry to hear that.

Answer 32

well what am i doing that would make it wrong?? @Hero

Answer 33

I'm not sure what you are doing wrong. You haven't shown your work yet

Answer 34

okay let me get all the answers i got and i will post them @Hero

Answer 35

No. I need to see everything you did.. Not just the answers you got.

Answer 36

okay well for (2)^3+(2)^2+13+4 i got -18

Answer 37

You got -18 for that? All the numbers in the expression are positive. Explain how you got -18 for that.

Answer 38

I put a + instead of a - in front of 13

Answer 39

my mistake, that's how it became a negative @Hero

Answer 40

wait they were all postives, i messed up again.

Answer 41

so the actual answer is 42 @Hero

Answer 42

the answer is 2^3-2(2)^2+2-2 @Hero

Answer 43

Finally...

Answer 44

Now do the same for the rest of the factors.

Answer 45

thanks.

Answer 46

You're welcome. and be careful with your calculations

Answer 47

yeah they confused me, now I am just curious, with the positive answer x+3 i would put in -3 right? @Hero

Answer 48

Yes, you were supposed to do like I suggested before which was to set

x + 3 = 0

and then solve for x

Answer 49

That way you know what x value to plug in

Answer 50

i did the other is 01

Answer 51

i mean -1