Question

find the derivative of the function.
arc sec2x

Answer 1

what do you have so far

Answer 2

Angela, are you allowed to use a table for derivatives of inverse trig functions?
If not, there is a way we can do this using a triangle, it just takes a few more steps than normal.

Answer 3

I honestly don't have a clue of wat to do :( @Decart @zepdrix

Answer 4

Answer the question silly billy >:O
Are you given access to a table of Inverse Trig Derivatives? :)

Answer 5

no I don't think so:) @zepdrix

Answer 6

\[\Large\bf y=arcsec 2x\qquad\qquad\to\qquad\qquad 2x=\sec y\]Understand what I did so far?
I just rewrote the relationship so we don't have that inverse function anymore.

Answer 7

that's possible?? :o and yes I understand:)

Answer 8

So what we want to do is some sneaky triangle math that you might remember back from Trig.

\[\Large\bf \sec y\quad=\quad 2x\quad=\quad \frac{2x}{1}\quad=\quad \frac{hypotenuse}{adjacent}\]We want to draw this relationship on a triangle.

Answer 9

Understand how we'll label this?

Answer 10

lol let me look at it a lil more xp

Answer 11

wait, does this apply if its f(x)=arc sec2x ??:) @zepdrix

Answer 12

You'll see how it connects later on D:

Answer 13

ok lol go on:) @zepdrix

Answer 14

So we'll label our sides according to our trig identity.