Question

Related Rates Help???

Answer 1

The Area, A of a aquare is increasing at 3cm^3 per minute. How fast is the side length of the square changing when A=576cm^3?

Answer 2

is A a cube? or why is the volume (cm^3) increasing instead of the area (cm^2)?

Answer 3

@eashy do you know how to graph ellipses when the number under the x is one

Answer 4

my mistake yeah it should be cm^2

Answer 5

this might help: http://tutorial.math.lamar.edu/Classes/Alg/Ellipses.aspx

Answer 6

like i know how to graph im just not sure about the number under the x being one does that mean i move left and right one or square root one for the coverticies of a vertical ellipse?

Answer 7

also A=s(t)^2; dA/dt=2s(t)*s'(t)=3; solve for s'(t) given s(t)=sqrt(576)

Answer 8

if the number under x is one, then i think you move left and right the square root of the number x^2+y^2/a is equal to

Answer 9

so if x^2+y^2/a=b^2, then move left and right by b

Answer 10

oh ok so it will be a decimal right?

Answer 11

depending on b, yes

Answer 12

eashy...i did that and got s'(t)=16

Answer 13

ok thanks can i show you the graph when im done so you guys can see if its right

Answer 14

but the back of the book says the answer should be 1/16

Answer 15

probably you made an arithmetic mistake somewhere

Answer 16

2*s(t)*s'(t)=3; s'(t)=3/(2*s(t))=3/(2*sqrt(576))

Answer 17

this is the graph that i got for (x-2)^2/1+(y-1)^2/4=1 which the problem my teacher gave me

Answer 18

ohh okay got it thanks!!

Answer 19

looks good

Answer 20

an easy way to check is to plug the vertices (x,y) into the equation and see if the equation works out

Answer 21

all the points in the image work :)