Question

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Answer 1

\[(a+b)^2=a^2+2ab+b^2\] might help

Answer 2

oh maybe not, i better write this down on paper

Answer 3

XD

Answer 4

yeah it helps
also note that
\[(a-b)^2=a^2-2ab+b^2\] add them up

Answer 5

or rather, subtract

Answer 6

im confused :/

Answer 7

me too, :)

Answer 8

\[(a+b)^2=a^2+2ab+b^2=4\\
(a-b)^2=a^2-2ab+b^2=4\\
(a+b)^2-(a-b)^2=4ab=0\]

Answer 9

ok this may be a stupid question where are you getting the variables from out of the limits,

Answer 10

i am ignoring the limits, because the limit of the square is the square of the limit, the limit of the product is the product of the limit, etc

Answer 11

so youre replacing the functions as the a/b's?

Answer 12

to be more precise, if
\[\lim_{x\to c}(f(x)+g(x))=2\] then
\[\lim_{x\to c}(f(x)+g(x))^2=4\] etc

Answer 13

and so
\[\lim_{x\to c}[f^2(x)+2f(x)g(x)+g^2(x)]=4\]

Answer 14

so really this has nothing to do with limits
it is like saying
"if \(a+b=2, a-b=-2\) then find \(ab\)

Answer 15

wait so the final result is 4?

Answer 16

0

Answer 17

beacuse its 4-4?

Answer 18

you can use simple way by lim (f + g ) = lim f + lim g = 2--> lim f = 2 - lim g
lim f - lim g = -2 --> lim f = -2 + lim g
then solve for lim g = 2 then plug back to get lim f =0 so, limf * lim g = 0

Answer 19

I stick with lim, so no more confused, right?

Answer 20

so what he did makes no sense..

Answer 21

no no, what he did makes sense to me. Just a little bit higher than my head, hehehe... so, I confused. I do my math by counting my finger first, if it doesn't work, I use calculator then. If not, math tools. He jumped to math tool and confused me. But his way is good.

Answer 22

hey, you are the guy who asked about computer science, right? which asked to use induction to prove C_n < 4 (n-1)^2, right?

Answer 23

right

Answer 24

waaaat? you ask 2 questions at 2 different levels. The first one about computer science is tooooooooo high and this question is tooooooo low. Why?????

Answer 25

lol, 2 different classes :/

Answer 26

but the gap is too big.

Answer 27

tis' the way it goes at the moment

Answer 28

to solve your first question, to a math student, he has to pass at least cal3. To this question , just cal1 can solve it

Answer 29

well, the only pre-req for the discrete math class here is advanced trig and precalc

Answer 30

so im taking calc 2a sametime as discrete math to answer your question

Answer 31

life is hectic :)

Answer 32

hehehe... good luck. I have a bunch of physics material to read.

Answer 33

gl

Answer 34

ty