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@Hero PLEASE HELP ME!
1st write 2 formulas. q = number of quarters....n = number of nickels "Peggy had 3 times as many quarters as nickels." q = 3n "She had $1.60 in all" 0.25q + 0.05n = 1.60
I've had 5 people tell me this question is invalid.
Now use substitution. Plug in 3n for q in the second equation. 0.25(3n) + 0.05n = 1.6 0.75n + 0.05n = 1.6 0.8n = 1.6 n = 2 q = 3n = 3*2 = 6 2 nickels 6 quarters
6 is indeed 3 times as many as 2 and 6 quarters and 2 nickels make $1.60
It's solvable, but the given answer choices appear invalid
Okay, but that means there are the same number of quarters as nickles
Yeah, and that's where I'm stuck :(
Can't be the second choice since 160 is meaningless
yeah, nevermind.
Are they referring to $160 or 160 total coins?
160 cents?
$1.60
Yeah, 160 cents
I'm pretty sure it's an erroneous set of answer choices.
Yep, the setup is still wrong. You can't mix amount of money with number of coins.
I agree with you 100% hero.
The second one would work if it were: 5n + 25*3n=160
Thank you for you time :) I better check with my teacher on this
Did your teacher write this problem?
Oh wait, this is due at the beginning of class!! Eek!
No
lol, she probably told you she didn't.
Rofl :D Maybe's there's extras credit for whoever catches the mistake :P
Good Problem: Teacher: "Yes I wrote it" Bad Problem Teacher: "No I would never write such a problem"
ROFL!!!! :P Totally! :D Thank you for you time!
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