@SolomonZelman Find the indicated real nth root(s) of a. Thank you for any help!
1. n=4, a=0
2. n=7, a=128
3. n=5, a=0
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OpenStudy (anonymous):
real nth root... just find all the nth roots and throw out all the imaginary ones
OpenStudy (anonymous):
Okay, can you show me how? =)
OpenStudy (anonymous):
what math class are you in?
OpenStudy (anonymous):
I'm in algebra
OpenStudy (anonymous):
are you in a unit about imaginary numbers?
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OpenStudy (anonymous):
No, my teacher gives us problems that we aren't learning in class.
OpenStudy (anonymous):
have you learned about imaginary numbers before?
OpenStudy (anonymous):
(just wondering what depth I need to explain it to)
OpenStudy (anonymous):
I have but I can't remember how to find the real nth root.
OpenStudy (anonymous):
I remember most of it so just the nth root!
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OpenStudy (anonymous):
for the real nth root yes
OpenStudy (anonymous):
so x^n=a
OpenStudy (anonymous):
Okay, thank you so much!
OpenStudy (anonymous):
do you want me to teach you or remind you how to find complex nth roots?
OpenStudy (anonymous):
Can you remind me?
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OpenStudy (anonymous):
So, for the first problem would the answer be x^4=0?
OpenStudy (anonymous):
the answer would be whatever x would be if x^4=0
OpenStudy (anonymous):
complex nth roots are found using:\[\sqrt[n]{r(\cos (\theta) + i \sin (\theta)}=\sqrt[n]{r}(\cos(\frac{ \theta ±2\pi }{ n })+ i \sin (\frac{ \theta ±2\pi }{n})\]
OpenStudy (anonymous):
have you ever seen something like that before?
OpenStudy (anonymous):
if not, you probably don't have to know it
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OpenStudy (anonymous):
I haven't seen that before
OpenStudy (anonymous):
=(
OpenStudy (anonymous):
ok, you don't have to know it
OpenStudy (anonymous):
I learned that in pre-calculus, so...
OpenStudy (anonymous):
Okay!
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