Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@austinL
OpenStudy (austinl):
Is it,
\(e^{2x}=4\)?
hartnn (hartnn):
or
\(\large e^x e^{2x}=4
\\?\)
OpenStudy (anonymous):
@hartnn yeh that
OpenStudy (austinl):
I would rewrite it as,
\(e^{x}\times e^{2x}=4\)
Then take the natural log of each side.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so x * 2x = 4
OpenStudy (anonymous):
wouldnt that make x squared ?
OpenStudy (austinl):
Yep, we would have,
\(2x^2=\ln(4)\)
OpenStudy (anonymous):
would that be my final answer ? or would it be \[x = \sqrt{ \frac{ \ln4 }{ 2}}\]
OpenStudy (austinl):
That is close, you need to simplify that.
\(\displaystyle x=\frac{\sqrt{\ln(4)}}{\sqrt{2}}\)
Do you know how to do that?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
no /:
OpenStudy (anonymous):
can i just plug it into my calculator ?
OpenStudy (austinl):
You need to multiply both top and bottom by \(\sqrt{2}\)
OpenStudy (anonymous):
i got x = .832 is that right ?
OpenStudy (austinl):
Remember what I said, does it tell you to give a decimal approximation? Do you have choices?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
no i have to write out my answer. its an online class
hartnn (hartnn):
wait what ?
OpenStudy (anonymous):
@hartnn wym ?
hartnn (hartnn):
\(\huge x^m \times x^n = x^{m+n}\)
OpenStudy (austinl):
It is \(x\times2x=2x^2\)
@hartnn
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
\(\huge e^x \times e^{2x} = e^{x+2x}\)
hartnn (hartnn):
x+2x = ln 4
x = (ln 4) /3
OpenStudy (anonymous):
im soooo lost
OpenStudy (austinl):
Oh my goodness.....
I can't believe I made that error...
OpenStudy (austinl):
hartnn is correct.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
where do i have to go back and check ?
hartnn (hartnn):
which step did u not get ?
OpenStudy (anonymous):
you confused me ,
OpenStudy (anonymous):
okay so ln on both sides gives me x * 2x = 4ln right ?
OpenStudy (anonymous):
ln 4 i mean
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
how x*2x ?
OpenStudy (austinl):
I made an error, it is,
x+2x=ln(4)
3x=ln(4)
OpenStudy (austinl):
x=ln(4)/3
OpenStudy (anonymous):
why plus ?
hartnn (hartnn):
\(\huge x^m \times x^n = x^{m+n}\)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (austinl):
Because I made an error. Go back and look at hartnn's posts.
OpenStudy (anonymous):
oh i see
OpenStudy (anonymous):
so 3x = 4ln
hartnn (hartnn):
so e^x e^2x = e^ (x+2x)
only then you take natural log on both sides
hartnn (hartnn):
3x = ln 4
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i take natural log to bring the x's down right ?
hartnn (hartnn):
yes
hartnn (hartnn):
and the fact that ln e =1
OpenStudy (anonymous):
so my answer is ln 4 / 3 and i have the choice to make it a decimal im guessing ?
OpenStudy (austinl):
We have,
\(\large{e^{x}\times e^{2x}=4\Rightarrow e^{x+2x}=4}\)
Then you take the natural log,
\(\large{x+2x=\ln(4)\Rightarrow3x=\ln(4)}\)
\(\large{\displaystyle x=\frac{\ln(4)}{3}}\)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (austinl):
I would leave it as is, that is the exact answer.
OpenStudy (austinl):
Good catch @hartnn
I made a silly error and you saw it, I would have guided them along the wrong path.... Silly me.