Question

PLEASE HELP ME ASAP. x^4+x^3-6x^2-14x-12=0. make a list of possible rational roots, test the possible roots until you find one that produces a remainder of 0,write the resulting cubic function,use synthetic division to find a second root that will reduce the cubic expression to a quadratic expression, use the quadratic formula to find the final two roots.

Answer 1

Which part don't you understand?

Answer 2

im stuck on the write the resulting cubic function part right now. the first root i found is -2 so i have (x+2) taken out but i don't know how to write the original function as a cubic function after taking out (x+2)

Answer 3

You have to use synthetic division to find (x^4+x^3-6x^2-14x-12)/(x+2)

Answer 4

thanks surjit!

Answer 5

np

Answer 6

and the second root being 3, what will the equation look like when it is reduced to a quadratic?

Answer 7

again use synthetic division like i did.

Answer 8

x^2+2x+2?

Answer 9

and after using the quadratic formula, will my final 2 roots be -2+/- √-4/2?

Answer 10

\[=-1\pm \iota \]

Answer 11

_1±i =-2±√-4/2?