Question

Midpoints?

Answer 1

\(\bf \large {\text{middle point of 2 points }\\
\left(\cfrac{x_2 + x_1}{2}\quad ,\quad \cfrac{y_2 + y_1}{2} \right)}\)

Answer 2

L is the midpoint of CD. If CL = 1/3x+8 and LD = 2/3X=4. What is the length of CD?

Answer 3

I know how to find midpoints @jdoe0001 but with the fractions I'm confused at where to start

Answer 4

so.... which one do you think is LONGER, CL or LD?

Answer 5

LD appears longer... but it's supposed to be middle?....

Answer 6

well... if LD is longer.... then that means L is not the midpoint, is it?

Answer 7

anyhow... neither is longer, since L is the midpoint, then CD is just as long as LD, thus CL = LD, thus \(\bf \cfrac{1}{3x+8}=\cfrac{2}{3x-4}\)

Answer 8

yes

Answer 9

CL is just as long as LD I meant, darn typos heheh

Answer 10

@surjithayer sorry I'm really bad at this but I got 3x=4

Answer 11

\(\bf \cfrac{1}{3x+8}=\cfrac{2}{3x-4}\implies 1(3x-4)=2(3x+8)\implies 3x-4=6x+16\)

subtract 16 and 3x from both sides

Answer 12

http://www.youtube.com/watch?v=ajHIHYqAD1Q

Answer 13

I got -20=3x

Answer 14

yeap now if you divide both sides by 3, then you'd end up with \(\bf \cfrac{1}{3x+8}=\cfrac{2}{3x-4}\implies 1(3x-4)=2(3x+8)\implies 3x-4=6x+16\\ \quad \\
-20=3x\implies \cfrac{-20}{3}=x\)

Answer 15

-6.67

Answer 16

the lenth of CD is CL + LD, thus \(\bf CD = CL + LD\implies \cfrac{1}{3x+8}+\cfrac{2}{3x-4}\\ \quad \\
\implies \cfrac{1}{3\left(\frac{-20}{3}\right)+8}+\cfrac{2}{3\left(\frac{-20}{3}\right)-4}\)