Question

What is the slope of the line between (-4, 4) and (-1, -2)?

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(-4\quad ,&4)\quad &(-1\quad ,&-2)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}
\\ \quad \\

y-y_1=m(x-x_1)\quad \textit{plug in your values and solve for "y"}
\)

Answer 2

\[slope = \frac {rise} {run}\]

rise means the change in the y direction from one pint to the next point.
from the point (-4, 4) to the point (-1, -2) there is a change in the y of -6 units. becuase we are going from 4 to -2, which is a difference of -6. so rise=-6
can u try to find the 'run' of the two points you have? or in other words find how many numbers are between -4 and -1

Answer 3

these are my options 1
2
-2
-1

Answer 4

hmm ohhh. it's just the slope, not the equation... hmm \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(-4\quad ,&4)\quad &(-1\quad ,&-2)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\)

Answer 5

i think it would be 2?

Answer 6

what did you get?