Question

how do I find the x intercept of an exponential function?

Answer 1

try googling the question first ^_^

Answer 2

I've tried already. They all link you to finding y intercepts for exponential functions

Answer 3

Would it be correct to just set y as 0? Then use log? Because that would work in some cases but lets say the equation was, y=2(3)^x
If I were to set y as 0, t hen I wouldn't be able to take 2 to the other side

Answer 4

yep, i'd set y=0 and solve for x using log

Answer 5

hmmm

Answer 6

How would that work though, because if the equation was 7=2(3)^ x and I set y = 0
0 = 2(3)^x
wouldn't I have to somehow get 2 to the other side? Or would I just do
0=2(Log3)^x?

Answer 7

what's the function?

Answer 8

yes I'd still set y = 0, since over the cartesian grid is where y = 0 anyway

Answer 9

I don't have a specific example from a textbook, I put a random equation above ^. I don't need exact numbers but I just need a process. y
=2(3)^ x

Answer 10

so would I have to just do this: 0=2(Log3)^x?

Answer 11

hmm....

Answer 12

well.... the short.... answer will be .. yes

Answer 13

then again \(3^x\) will never yield 0, so that means the graph never touches the x-axis since it'd be an asymptote

Answer 14

http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIyKjNeeCIsImNvbG9yIjoiI0RCMjM3QyJ9LHsidHlwZSI6MCwiZXEiOiItMiozXngiLCJjb2xvciI6IiMzMTE5RTYifSx7InR5cGUiOjEwMDB9XQ--

Answer 15

Alright thanks a lot. Appreciated :)