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1/7^(x-1)=1/2401 What is x?
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2401 = 7^4 can you solve now?
\[\large \frac{ 1 }{ 7^{x-1} } = \frac{ 1 }{ 2401 } = \frac{ 1 }{ 7^4 }\]
I ended up with x=-3 but my teacher told me my answer needed to be positive.
\[\large \frac{ 1 }{ 7^{x-1} } = \frac{ 1 }{ 7^4 }\] The only way that is possible is when x - 1 = 4 (because both bases are 7. The only way they can be equal is when the exponents are the same.) solve x - 1 = 4
ok! i see where I went wrong! Thank you!
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