The turntable reaches an angular speed of 45 rev/min in 4.10 s after being turned on. What is its angular acceleration?
You are given your initial and final velocities, as well as your time value, so you should be able to solve it with a simple acceleration formula. However, the catch is that your time is in seconds and your velocity in minutes. I would suggest doing 4.1/60 to get seconds into minutes, and then doing 45 divided by that number. Hope that helped.
The "angular kinematics" are exactly like their linear counterparts. So if you would normally find the linear acceleration using \[a = \frac{ \Delta v}{\Delta t}\] then similarly, you would find the angular acceleration \[ \alpha = \frac{\Delta \omega}{\Delta t}\] Then like @Potatocracy said, be sure to convert your angular velocity from rev/min to rev/sec \[ \omega = \Big( \frac{4.5 \ rev}{ min} \Big) \Big( \frac{1 \ min}{60 \ s } \Big)= \frac{4.5 \ rev}{ 60 s}\]
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