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Physics 18 Online
OpenStudy (anonymous):

A playground merry-go-round of radius 2.5 m has a moment of inertia 204 kg.m2 and is rotating at 13 rev/min about a frictionless vertical axle. Facing the axle, a 21 kg child hops onto the merry-go-round, and manages to sit down on the edge. What is the new angular speed of the merry-go-round? Answer in units of rev/min

OpenStudy (anonymous):

You need to use conservation of angular momentum by calculating the new moment of inertia once the kid hops on - you can treat her as a point mass at radius r \[ L_i = L_f\] \[I_{i}\omega_i=I_f\omega_f\] \[ \quad \quad I_f=I_i + m_cr^2\] \[m_c = \text{mass of child} \\ r = \text{ radius of merry go round}\]

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