A 14.01 g sample reacts with g of h2 to form ammonia (NH3). if ammonia is the only product, what mas of ammonia is formed.
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OpenStudy (anonymous):
0.0160M
OpenStudy (anonymous):
A 14.01 g sample reacts with g of h2 to form ammonia (NH3). if ammonia is the only product, what mas of ammonia is formed
OpenStudy (anonymous):
@Nutcase482
OpenStudy (anonymous):
@Emmalineh123 is also good with math. She'd probably be able to help you more than me!
OpenStudy (anonymous):
at least try please MrNutcase.
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OpenStudy (anonymous):
17.01g
OpenStudy (anonymous):
I'm pretty sure it is 17.01g
OpenStudy (anonymous):
can u do this one How many milliliter of a 0.184 M NaNO3 solution contain 0.113 moles of NaNo3? help
OpenStudy (anonymous):
614ml
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
ok how many grams of N2(g) can be made form 9.05 g of NH3 reacting with 45.2 g of Cuo?
2 NH3(g)+3CuO(S) N2(g) +3Cu(s)+3h20(/)
OpenStudy (anonymous):
Oh geeze. I'm not sure about this one.
OpenStudy (anonymous):
hold on how about this one
OpenStudy (anonymous):
according to the following balanced reaction, how many moles of KOH will be formed from 5.44 moles of H20 ssume an exess of KO
4 KO(s)+2H20(I) 4 KOH(S)+ O2(g)