can some one tell me if this answer is correct
What answer?
This is not, because there is no answer.
nobody can help you without the answer
\[\ln (x^{6}\sqrt{5-x}), 0<x <5\] \[\ln x^{6}+\frac{ 1 }{ 2 }\ln 5-x\]
can you show us what you did, please?
I used the formula M*N= M+N
But should your equation be equal to ZERO?
You didn't say it is equal to something, are you simplifying?
\[Ln(x ^{6}*\sqrt{5-x})= \ln x ^{6}+ \ln \sqrt{5-x}\] and then to remove the square root I rise to the power of 1/2
Ok, that makes sense now. if you were asked to expand, then that's it.
well it says write the expression as a sum of logarithms so I guess what they are asking for. Thanks
Yep, you got it then! For more help, there is a link with all rules, http://www.rapidtables.com/math/algebra/Ln.htm
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