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OpenStudy (anonymous):
@Emmalineh123
OpenStudy (anonymous):
how many grams of N2(g) can be made from 9.05 f of NH3 reacting with 45.2 g of CuO?
2 NH3(g) +3CuO(s) N2(g)+Cu(s)+3 H20(/)
OpenStudy (homeworksucks):
F?
OpenStudy (homeworksucks):
what do you mean by 9.05 f?
OpenStudy (anonymous):
how many grams of N2(g) can be made from 9.05 of of NH3 reacting with 45.2 g of CuO?
2 NH3(g) +3CuO(s) N2(g)+Cu(s)+3 H20(/)
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OpenStudy (homeworksucks):
I'm going to assume you mean 9.05 grams
OpenStudy (anonymous):
yes
OpenStudy (homeworksucks):
So first,you want the amount in moles that you have of Nh3
OpenStudy (homeworksucks):
and same with copper oxide
OpenStudy (anonymous):
ok
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OpenStudy (homeworksucks):
So, once you have that, find the amount needed of CuO to react with NH3, how much will actually be used. You can use your mole ratio (for every so and so moles of CuO there are so and so moles of NH3), and use your molar mass to get an amount in grams If that number is bigger than what you have of NH3, then the insufficient amount of NH3 is LIMITING the extent of the reaction, if it is more than, you have more than enough, or EXCESS.