Solve for x by completing the square: 4x2 + 6x - 6 = 0
A. (-3+√33)/4, (-3-√33)/4
B. (3+√33)/4, (3-√33)/4
C. 3, -2
D. 1, 6

Question

Solve for x by completing the square: 4x2 + 6x - 6 = 0 
	A.	(-3+√33)/4, (-3-√33)/4
	B.	(3+√33)/4, (3-√33)/4
	C.	3, -2
	D.	1, 6

anonymous · Answer

simply tak out 2 common and then use shreedharacharya

campbell_st · Answer

leave the common factor in as 

$$(2x)^2 = 4x^2... $$

campbell_st · Answer

the 1st term in the binomial is 2x   since 

$$(2x)^2 = 4x^2$$

so them middle term is  $$2 \times 2x + ? = 6x$$

find the value of ?

then square it... 

then you'll have 

$$(2x + ?)^2 - 6 - ? = 0$$

then when you have the perfect square you can then look at solving...

cenaida · Answer

thanks so the answer is B?

campbell_st · Answer

oops should be 

$$(2x + ?)^2 - 6 - ?^2 = 0$$

campbell_st · Answer

I don't know... I just showed you how to complete the square so you can find a solution.

cenaida · Answer

but can you check if im right?.............

campbell_st · Answer

oh... and the answers not B

campbell_st · Answer

but if you wait long enough someone always gives the answer

anonymous · Answer

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