Question

I really need help
what are all the zeros for
y=x(x+5)(x+4)

Answer 1

0,-5,-4

Answer 2

x(x+5)(x+4)=0
x=0 or x+5=0 or x+4=0

Answer 3

thanks

Answer 4

no problem

Answer 5

y=x(x+5)(x+4)

To find the zeroes equate y to 0

then

y=x(x+5)(x+4) = 0

Thus

First zero can be =>x = 0/(x+5)(x+4) = 0
Second zero can be => x+4 = 0/x(x+5)
=> x+4=0
=> x = -4
Third zero can be => x+5 = 0/x(x+4)
=> x+5 =0
=> x =-5

And thus the three zeroes of this third degree polynomial will be 0,-4,-5

Understood? :)

Answer 6

you want the x values that make y = 0

The main idea is if you multiply three numbers, say A * B *C
if any is 0, you will get 0.
in your case, the three "numbers" are x * (x+5) * (x+4)

if any of the three are zero, that is an answer.
you get 3 different values