Question

How many grams of O2(g) are needed to completely burn 27.5 g of C3H8(g)?

Answer 1

burning is referring to combustion reaction, meaning, prodcts will be: \(\sf \color{red}{CO_2+ H_2O}\) So, write the equation down first and balance it, if needed. Is your first step! Can you do that.

Answer 2

no

Answer 3

C3H8+5O2=3CO2+4H2O

Answer 4

is that the answer?

Answer 5

thats just the balanced equation

Answer 6

i need the ph solution

Answer 7

you're on the wrong thread

Answer 8

what

Answer 9

this is my question. not yours. your post is the thread below mine on the left side of the screen

Answer 10

k

Answer 11

Anyways, lol. Yes, once it is balanced, now you need to use dimensional analysis to go from grams of propane \(\rightarrow\) grams of oxygen.

Answer 12

So, you have 27.5 g \(\sf \color{}{C_3H_8}\) \(\sf \color{}{\times \frac{mole~C_3H_8}{grams~of~C_3H_8}}\). nOTICE how the units of grams cancel out for butane!

Answer 13

To find the molas mass, look at your periodic table, add up all the values of 3carbons + 8 hydrogens. Remember that molar mass is in units of \(\sf \color{Red}{\frac{grams}{mole}}\)

Answer 14

Ok, may take a bit.

Answer 15

44.0962 is the molar mass

Answer 16

haha no I'm not sure

Answer 17

nO WAIT nevermind you're right. i was thinking butane. sorry.

Answer 18

awesome

Answer 19

Ok, now follow the step i provided above \(\sf \color{red}{ 27.5~ g~propane \times \frac{mole~of~propane}{44.10~g~propane} = mole~of~propane}\)

Answer 20

Once you have moles of propane, you can simply multiply by 5! Since you have 5 moles of
O\(_2\) and that is your final answer.

Answer 21

3.18?

Answer 22

Is that what you got after multiplying moles \(\times\) 5?