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The half-life of thorium-229 is 7340 years. How long will it take for a sample of this substance to decay to 20% of its original amount? A=Aoe^kt
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set \[\left(\frac{1}{2}\right)^\frac{t}{7340}=.2\] and solve for \(t\)
change of base formula gives \[\frac{t}{7340}=\frac{\ln(.2)}{\ln(.5)}\] so \[t=\frac{7340\ln(.2)}{\ln(.5)}\]
ok
you might notice i did not use \[A=A_0e^{kt}\] you can use that too but it takes longer, because first you have to find \(k\) i only used the numbers that were given
so the answer is?
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you need a calculator at this point, if you want a decimal
this is what i get http://www.wolframalpha.com/input/?i=7340*ln%28.2%29%2Fln%28.5%29
that doesnt help
so i take .2/.5? i got .4
thanks
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