Cone A has a height of 3 meters and a radius of 2 meters. Cone B has the same radius, but the height is 6 meters. Calculate the volume of each cone. Which conclusion is correct? A) The volume of cone A is twice the volume of cone B. B) The volume of cone B is twice the volume of cone A. C) The volume of cone B is 4 times the volume of cone A. D) The volume of cone B is three times the volume of cone A.
Volume of a cone: \[V=\frac{ 1 }{ 3 }\pi r ^{2}h\] For Cone A: \[V _{A}=\frac{ 1 }{ 3 }\pi r _{A} ^{2}h _{A}\] For Cone B: \[V _{B}=\frac{ 1 }{ 3 }\pi r _{B} ^{2}h _{B}\] But we know: \[r _{A}=r _{B}\] and \[h _{B}=3h _{A}\] and we can also see that a-d are all ratios, so we plug these into \[V_{B}\] and calculate: \[\frac{ V _{B} }{ V _{A} }=\frac{ 1/3 \pi r _{a}^{2}(2*h _{a}) }{ 1/3 \pi r _{a}^{2}(h _{a}) }\] And that gives you what???
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