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Mathematics 15 Online
OpenStudy (anonymous):

ap calc question with answer need work!!! help please equation will be attached.

OpenStudy (anonymous):

a point moves along a curve Y=\[2x ^{2}+1\] in such a way that the y value is decreasing at the rate of 2 units per second. At what rate is x changing when x=2/3

OpenStudy (anonymous):

answer is decreasing 1/3 units/sec

OpenStudy (anonymous):

? lol

OpenStudy (anonymous):

\[y=2x^2+1\] \[\frac{dy}{dt}=4x\frac{dx}{dt}\] and you are told that \(\frac{dy}{dt}=-2, x=\frac{2}{3}\) solve for \(\frac{dx}{dt}\)

OpenStudy (anonymous):

wouldnt that equal -3/4???

OpenStudy (anonymous):

@satellite73 can you help me?

OpenStudy (ranga):

yes dx/dt = -3/4

OpenStudy (anonymous):

but the answer is -1/3 so i dont think that was the correct equation for what im looking for.

OpenStudy (ranga):

For the set of information you have provided dx/dt = -3/4. Go through the question carefully and see if there is any typo or missing info.

OpenStudy (anonymous):

x actually equals 3/2 thanks

OpenStudy (anonymous):

hahaha

OpenStudy (ranga):

then it is -1/3 indeed.

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