Question

4y/y+5=5y/y-4

Answer 1

I assume that you mean \(\dfrac{4y}{y+5}=\dfrac{5y}{y-4}\)?

Answer 2

Use cross multiplication and you get \(4y(y-4)=5y(y+5)\).

Answer 3

Then expand them and put everything on the left hand side :)

Answer 4

\[\large \frac{ 4y }{ y + 5 } = \frac{ 5y }{ y-4 }\]
To solve for y, we use cross multiplication.
Doing so, results in this.
\[\large 4y(y-4)= 5y(y+5)\]
From there distribute the values to the respective values in the parentheses.
You result in:
\[ \large 4y^2-16y = 5y^2 + 25y\]
The next step is get everything on one side, and zero on the other.
Let's start by subtracting 5y^2 and 25y from both sides.
\[\large -y^2 - 41y = 0\]
Divide everything by -1.
\[\large y^2 + 41y = 0\]
Now, input your values of a,b, and c.
a = 1 , b= 41, c = 0
Into the quadratic formula.
\[\large y=\frac{ -b \pm \sqrt{b^2-4(a)(c)} }{ 2(a) }\]

Answer 5

Actually.

Answer 6

\[\large y^2 + 41 y = 0\]
has gcf so we can just do that.
\[\large y(y+41) = 0\]
so you have.
y = 0
and
y + 41 = 0
y = -41

Answer 7

what point does it have to give him directly the answer

Answer 8

I've explained it completely.

Answer 9

but effort appreciated, i'll medal you :D

Answer 10

Thanks.

Answer 11

no problem :)

Answer 12

Thank you