Question

Help anyone?

Answer 1

I can

Answer 2

Here is a stupid way for you to know how to do:
So noble gas (except \(He\)) has an octet structure.
As the name suggests, they are nobles. Everyone wanna be nobles.
They'd lose electron or steal electron to be nobles (to have 8 electrons on the outermost occupied shell)

Answer 3

For group one, they'd give off 1 electron.
Group two, 2.
For group seven, they'd steal 1 electron to have 8 electrons.
(remember the group number is indicating how many electrons it has in the outermost electron shell)

Answer 4

Which group is potassium in? And how many electrons will it give up/steal to become a noble? If so, what's its charge?
(remember, electrons have a negative charge, so losing an electron would result in a potivie charge)

Answer 5

Welcome @UnkleRhaukus :D

Answer 6

Therefore how many electrons will it give off/steal?

Answer 7

exactly :D

Answer 8

so what's its charge?

Answer 9

yep :D

Answer 10

answer the same questions for oxygen and nitrogen

Answer 11

Nope, this is just the monoatomic part :)

Answer 12

It's a cation (+ve) or an anion (-ve)?

Answer 13

yep

Answer 14

if it's an anion, you change the ending to -ide.

Answer 15

Like the anion of hydr\(\underline{ogen}\) is hydr\(\underline{ide}\) ion.

Answer 16

yep :D

Answer 17

oh you use a different style of naming

Answer 18

oh yes

Answer 19

therefore it would be better for him to steal electrons than to give off

Answer 20

no it doesn't give off electrons :)

Answer 21

they wanna be nobles, who have 8 electrons.

Answer 22

so how many electrons must they steal?

Answer 23

oh sorry i meant outermost electron shell

Answer 24

and @nincompoop actually taught me a good way to teach people lol
he taught me to use other examples, so here it goes.

\(Al\) is in group three, so it must lose 3 electrons to become noble(stable octet), and therefore forms \(Al^{3+}\) ions.
\(S\) is in group six, so it must steal 2 electrons to become noble(stable octet), and therefore forms \(S^{2-}\) ions.
Two \(Al^{3+}\) atoms give off 6 electrons, which require three \(S^{2-}\) to receive, and therefore forms the compound \(Al_2S_3\)

Answer 25

Sorry I can't explain things well. @UnkleRhaukus and @derek11111 may be able to help you.