Question

Please help me solve this simultaneous equation 3x-2y=10 2x+5y=15

Answer 1

This is a system of equations, right?

Answer 2

and does it want you to solve by elimination, substitution, etc?

Answer 3

@Jneil ?

Answer 4

Am not sure i guess.

Answer 5

Okay, well I used the elimination method and this is what I got..
\[x= \frac{ 80 }{ 19 }, y=\frac{ 25 }{ 19 }\]

Answer 6

Is this a multiple choice question?

Answer 7

No

Answer 8

Do you have to show work?

Answer 9

Yes

Answer 10

Okay, give me a minute!

Answer 11

Ok

Answer 12

Multiply each equation by the value that makes the coefficients of y equal. This value is found by dividing the least common multiple of the coefficients of y by the current coefficient. In this case, the least common multiple is 10.

5⋅(3x−2y=10)
2⋅(2x+5y=15)

Multiply each equation by the value that makes the coefficients of y equal. This value is found by dividing the least common multiple of the coefficients of y by the current coefficient. In this case, the least common multiple is 10.

5⋅(3x−2y)=5(10)
2⋅(2x+5y)=2(15)

Multiply 5 by each term inside the parentheses.
5⋅(3x−2y)=50
2⋅(2x+5y)=2(15)

Multiply 5 by each term inside the parentheses.
15x−10y=50
2⋅(2x+5y)=2(15)

Multiply 2 by each term inside the parentheses.
15x−10y=50
2⋅(2x+5y)=30

Multiply 2 by each term inside the parentheses.
15x−10y=50
4x+10y=30

Answer 13

Add the two equations together to eliminate y from the system.

Answer 14

Am not getting it

Answer 15

Divide each term in the equation by 19.
x=80/19

Substitute the value found for x into the original equation to solve for y.

15(80/19)−10y=50

Multiply 15 by each term inside the parentheses.
1200/19−10y=50

Move all terms not containing y to the right-hand side of the equation.
−10y=−250/19

Divide each term in the equation by −10.
y=25/19
This is the final solution to the independent system of equations.

Answer: x= 80/19, y=25/19

Remember, I used the elimination method.

Answer 16

Ok am gonna try it

Answer 17

You add the two together and are trying to get x along and then y alone, using the simplest equation.

Answer 18

Can you use the substitution method please.