Question

Prove: C-(ANB)=(C-A)U(C-B)

Answer 1

again you want to prove the left is equal to the right vice versa
so start off by letting \[x \in (C - (AnB))\] and work from there

Answer 2

I know, but then you run into the problem of getting the "Or" in there. Or is there something I'm missing?

Answer 3

alright let me try this out

Answer 4

I've gotten to "which means x (is not in) A and x (is not in) B." But I can't fit the "or" in

Answer 5

\[x \in C \]and \[x \notin (AnB) \] so
\[x \notin A \]and \[x \notin B \]
so \[x \in (C - A)\]
or
\[x \in (C - B) \]


hm... my memory is still fuzzy from when i took this classs..

Answer 6

Thanks!

Answer 7

if i rmember correctly the and statement becomes and or statement when you have something in one set and not the other

your welcome and i hope i gave you some idea