Prove: C-(ANB)=(C-A)U(C-B)

Question

anonymous · Answer

again you want to prove the left is equal to the right vice versa
so start off by letting $$x \in (C - (AnB))$$ and work from there

anonymous · Answer

I know, but then you run into the problem of getting the "Or" in there. Or is there something I'm missing?

anonymous · Answer

alright let me try this out

anonymous · Answer

I've gotten to "which means x (is not in) A and x (is not in) B." But I can't fit the "or" in

anonymous · Answer

$$x \in C $$and $$x \notin (AnB) $$ so
$$x \notin A $$and $$x \notin B $$
so $$x \in (C - A)$$ 
or
$$x \in (C - B) $$


hm... my memory is still fuzzy from when i took this classs..

anonymous · Answer

Thanks!

anonymous · Answer

if i rmember correctly the and statement becomes and or statement when you have something in one set and not the other

your welcome and i hope i gave you some idea