I need help with solving this system by using elimination Plz help I have no idea how to do this. And plz don't just give me answers
First pick a variable to eliminate. Try eliminating z first from equations 1 and 2: Multiply the second equation by -3 and add it to the first and that will get rid of the z. Eliminate z from equations 2 and 3. Multiply the second equation by -3 and add it to the third and that will get rid of the z. You will be left with 2 equations and two unknowns x and y which you can solve by eliminating one of the variables, say, y.
I do not really understand.
-2x + 2y + 3z = 0 ----- equation 1 -2x - y + z = -3 ----- equation 2 2x + 3y + 3z = 5 ----- equation 3 Eliminate z from equations 1 and 2: Multiply equation 2 by -3: +6x + 3y - 3z = +9 ----- equation 4 Add this to equation 1: -2x + 2y + 3z = 0 ----- equation 1 Add: 4x + 5y = 9 ----- equation 5 Now can you try the same method and eliminate z from equations 2 and 3?
for equation 2 and 3 is it 6x+3y-3z=9 -6x-9y-9z=-15 ---------------- -6y-12z=-6 ???
You multiplied the wrong equation by -3. We wanted to eliminate z from equations 2 and 3. To do that, multiply the second equation by -3 and add it to to the third.
If you look at the coefficient of z in equation 2 it is: +1 If you look at the coefficient of z in equation 3 it is: +3 So if I multiply the second equation by -3 I will make the z coefficient -3 which when added to equation 3 will cancel out z.
6x+3y-3z=9 2x+3y+3z=5 ------------- 8x+6y=14 ???
Yes.
Call 8x+6y=14 equation 6. Eliminate x from equations 5 and 6.
4x + 5y = 9 ----- equation 5 8x + 6y =14 ----- equation 6. Try to eliminate x. The coefficient of x in equation 5 is: 4 The coefficient of x in equation 6 is: 8 What should we do to make the coefficient of x in equation 5 to be -8 so it will cancel out with the coefficient of x in equation 6 which is +8 ?
times by -2??
Exactly! Multiply equation 5 by -2 and add it to equation 6 and the x will be gone. You will be just left with y which you can solve easily.
-4y=-4
solve for y by dividing both sides by -4
=1
yes. Put y = 1 in equation 5 and solve for x.
would x be 1?
Yes. Put x = 1 and y = 1 in equation 2 and solve for z. (BTW, you can put x and y values in any of the first three equations to solve for z put choose the one that is the easiest.)
is it 0 because...-2(1)-1+0=-3
Yes! Well done! x = 1, y = 1 and z = 0 is the solution.
Alright thank you so much for your time!! :)
you are welcome.
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